How do you find the perimeter of a rectangle with the dimensions (x^2+2x-16) ft (length)
and (x+5) ft (width)

(2x²+6x-22) ft

Step-by-step explanation:

l = (x²+2x-16) ft

and w = (x+5) ft

the Perimeter =

2(x²+2x-16) +2(x+5)

= 2x²+4x-32+2x+10

= 2x²+6x-22

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!