you sight a rock climber on a cliff at a 32° angle of elevation. your eye level is 5.5 feet above the ground and you are 1000 feet from the base of the cliff. what is the approximate height of the rock climber from the ground?

630 feets

Step-by-step explanation:

From the triangle attached :

Using trigonometry, the height h, which is the height of climber to your eye level :

Tan θ = opposite / Adjacent

Tan 32 = h / 1000

h = tan 32 * 1000

h = 0.6248693 * 1000

h = 624.86935

Height from the ground :

624.86935 + 5.5

= 630.369 feets

= 630 feet

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it