Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement. (a) Suppose I draw n times. Let X., be the number of times I saw a green ball followed by a yellow ball. Calculate the expectation Ex, (b) Let y be the number of times I drew a green ball before the first white draw. Calculate E[Y]. Can you give an intuitive explanation for your answer

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green

Number of yellow

Number of white

Probability of Green Followed by yellow P(GY) ball

Generally the equations for when n is even is mathematically given by

Therefore

Generally the equations for when n is odd is mathematically given by

b)

Probability of drawing white ball

Therefore

Therefore

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

answer: 819.89 miles across america

step-by-step explanation: