The combination locks on the lockers at Hillside School have numbers from 0 through 39 (inclusive). A locker combination consists of three different numbers, where the order matters. Because of the way the locks are manufactured, all three numbers are even or all three numbers are odd. How many combinations are possible

13680

Step-by-step explanation:

Since we have number from 0 to 39 inclusive, there are 40 number all together.

Now there are 20 odd numbers and 20 even numbers since half of the the numbers are odd and half even.

Now, since we require 3 numbers for our locker combination which are either all even or all odd, the number of ways we can arrange 3 numbers from 20 when the order matters is ²⁰P₃ = 6480 ways for either odd or even numbers. So, for both odd and even numbers, we have the sum of even and odd number of ways ²⁰P₃ + ²⁰P₃ = 2 × ²⁰P₃ = 2 × 6480 = 13680. So, we have 13680 combinations of locks.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )