IF YOU ANSWER CORRECTLY I WILL GIVE BRAINIEST!, 2. At a fair, each person can spin two wheels of chance. The first wheel has the numbers 1, 2, and 3. The second wheel has the letters A and B. (d) List all the possible outcomes of the compound event. (e) If you spin both wheels, what is the probability that you get either a 1 or an A? Explain.

And pls don’t answer if you don’t know it.

Possible outcomes: 1a 1b 2a 2b 3a 3b  

Outcomes for spinning a one = 2

1a, and 1b 2/6

Outcomes for spinning an "a" = 3

1a, 2a, and 3a.

1a is already in the first set so we can exclude it. 2/6

2/6+2/6=4/6

There is a 4/6 or 2/3 chance of getting either an a or an 1

(d) 1A, 1B, 2A, 2B, 3A, 3B

(e)  2/3 or 66.66% chance

Explanation is below

Step-by-step explanation:

(d) The Total outcomes are 3*2 = 6, because there are 3 numbers and 2 letters.

The outcomes are:

1A

1B

2A

2B

3A

3B

(e) Of the 6 outcomes, 3 of them have A and 2 of them have 1. But one of them has an A and 1, so it is 4 outcomes: 1A, 1B, 2A, and 3A.

So it is 4/6 = 2/3, or 66.66...% chance

da freeck kinda math is this just drop out

step-by-step explanation: