In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. Find an equation for the population, P, of the school t years after 2009.

P(t) = 100t + 1900

Step-by-step explanation:

∆P = 2500 - 1700 = 800

∆t = 2017 - 2009 = 8

m = ∆p/∆t = 800/8 = 100

b = initial pop = 1900

using slope intercept form

P(t) = 100t + 1900

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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