Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frosting with cream filling, and the rest had chocolate frosting with sprinkles. What fraction of the donuts had sprinkles? There are 12 donuts in a dozen.

22/24

ALL TOGETHER there is 24 donuts.

take half of 24, or 24 divided by 2, and you get 12.

so we know 12 of the donuts are vanilla with sprinkles.

then 2 had strawberry frosting and the rest had chocolate and sprinkles.

we took 12 away so we only have twelve left and if 2 of those 12 are strawberry with no sprinkles and the rest are chocolate WITH sprinkles, this means 10 are chocolate with sprinkles.

so 10 chocolate and sprinkles +12 vanilla and sprinkles=22 donuts with sprinkles out of 24 donuts total

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47