The equation of a circle is (x+8)2+(y-5)2=14. What are the coordinates of the center of the circle?

(-8,5)

Step-by-step explanation:

The standard form of the equation of a circle is expressed as;

(x-a)^2+(y-b)^2 = r^2 where;

(a, b) is the centre

r is the radius

Given the equation (x+8)^2+(y-5)^2=14.

Compare the two expressions

-a = +8

a = -8

Similarly;

-b = -5

b = 5

Hence the centre of the circle is at (-8,5)

the answer is (-4,-4)

hope this ! : d