If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3

would be when .

Step-by-step explanation:

The question states that varies "inversely" as . In other words, there is a non-zero number (a constant) such that:

.

The challenging part is to find the value of in this equation.

Given that when , replace the in this equation with and with . This equation should still be valid:

.

Solve for :

.

Hence, the relation between and becomes:

.

Find the value of when by replacing the in this equation with .

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In other words, the value of would be when .

your answer is b ^w^ hope i

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)