✅![\frac{4}{ \sqrt{x} - \sqrt{x - 2} } \\\\ = \frac{4}{ \sqrt{x} - \sqrt{x - 2} } \times \frac{ \sqrt{x} + \sqrt{x - 2} }{ \sqrt{x} + \sqrt{x - 2} } \\ \\ = \frac{4( \sqrt{x}) + 4( \sqrt{x - 2} )}{( { \sqrt{x} )}^{2} - { (\sqrt{x - 2} })^{2} } \\ \\ [∵(a + b)(a - b) = {a}^{2} - {b}^{2} ] \\ \\ = \frac{4 \sqrt{x} + 4 \sqrt{x - 2} }{x - (x - 2)} \\ \\ = \frac{4 \sqrt{x} + 4 \sqrt{x - 2} }{x - x + 2} \\ \\ = \frac{4( \sqrt{x} + \sqrt{x - 2} ) }{ 2} \\ \\= 2( \sqrt{x} + \sqrt{x - 2} )](/tpl/images/1366/4281/0379e.png)
Which choice is equivalent to the fraction below when x >= 2
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Mathematics, 08.06.2021 06:00 damientran
Which choice is equivalent to the fraction below when x >= 2
Answers: 3
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