A sample proportion of 0.36 is found. To determine the margin of error for this statistic, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.36. The minimum sample proportion from the simulation is 0.28, and the maximum sample proportion from the simulation is 0.40.

The margin of error of the population proportion is found using half the range.

What is the interval estimate of the true population proportion?

(0.30,0.42)

(0.20,0.52)

(0.24,0.48)

(0.22,0.50)

(0.30, 0.42)

Step-by-step explanation:

Given the sample proportion is = 0.36

Number of trials required for determining the margin of the error = 100

Sample size, n = 50

The point estimate = 0.36

The minimum sample proportion form the simulation = 0.28

The maximum sample proportion from the simulation = 0.40

Also the margin of the error of population proportion is found by using the half of the range.

Therefore, the interval estimate for the true population proportion is = (0.30, 0.42)

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

4932,9180,7625 are divisible by 9