You have a $9000 bond that earns 3% interest compounded quarterly. How much is the bond word at 6 years?

$10,667.66

Step-by-step explanation:

The formula for calculating the compound interest is expressed as:

A = P(1+r/n)^nt

P is the principal = $9000

r is the rate = 3%

time t = 6years

n = 1/4

Substitute

A = 9000(1+0.03/(1/4))^6/4

A = 9000(1+0.03(4))^1.5

A = 9000(1+0.12)^1.5

A = 9000(1.12)^1.5

A = 9000(1.1853)

A = 10,667.67

Hence the amount after 6 years is $10,667.66

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer: i believe the answer is e

step-by-step explanation: