A poll is given, showing 60% are in favor of a new building project. If 7 people are chosen at random, what is the probability that exactly 5 of them favor the new building project?

Round this value however you need to.

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Explanation:

We use the binomial distribution here. The formula for that is

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

where the n C k refers to the nCr combination formula

simply replace r with k.

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So,

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

P(5) = (7 C 5)*(0.6)^5*(1-0.6)^(7-5)

P(5) = 21*(0.6)^5*(0.4)^(2)

P(5) = 21*0.07776*0.16

P(5) = 0.2612736

This decimal value is exact (meaning there aren't any other digits after that last '6'). Round this value however you need to.

There's roughly a 26.1% chance of getting exactly 5 people to be in favor of the project.

45

step-by-step explanation:

30+15

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3