A card is drawn randomly from a standard 52 card deck. Find the probability of drawing the given card. NO LINKS ​

Answers:

Explanations:

Problem 7)

There are 2 red aces (hearts, diamonds) out of 52 cards total, so 2/52 = 1/26 is the probability of picking a red ace.

Problem 8)

There are 4 kings out of 52 cards total, so 4/52 = 1/13 are the odds of picking a king.

This is the same as say focusing on one suit (eg: clubs) and finding the probability of pulling out a king.

Problem 9)

There are 3 face cards per suit (Jack, Queen, King) so 3*4 = 12 face cards in all. The odds of picking a face card are 12/52 = 3/13. That makes 10/13 the odds of not picking a face card, since 3/13+10/13 = 1.

Problem 10)

The answer is 1/2 because half of the cards are red.

You could say 26/52 = 1/2 since there are 26 red cards out of 52 cards total.

Problem 11)

There are 4 copies of '2' and 4 copies of '3', so there are 4+4 = 8 cards we want to avoid. The probability of picking either of them is 8/52 = 2/13. The odds of not picking any of these cards is 11/13  (refer to problem 9).

Problem 12)

We have 4 copies each of '7', '8' and '9'

That gives 4*3 = 12 cards total we want to pick.

So 12/52 = 3/13 is the answer.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: