1. 2x(11-6) +2x(42 /7) 2. 3x[(10-8+(12/4)] 3. [(1x5)+(18/9)]x 3+ 2

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

what are you trying find out?

step-by-step explanation: