A ladder 17m long rests against a vertical wall. The foot of the ladder is 8m away from the base of the wall. How high up the wall will the ladder reach?

So the high of the of the wall will be, 15m

Step-by-step explanation:

You can use Pythagoras theorem, c^2=a^2+b^2.

Take the length of the ladder as c, the foot of the ladder as (a), and the high of the wall as (b).

So :

c^2=a^2+b^2

(17m)^2= (8m)^2+ b^2

289m^2 = 64m^2 + b^2

289m^2 - 64m^2 = b^2

225m^2 = b^2

15m = b

q: 92 degrees

hope i ^-^

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula