Find the magnitude and direction of AB vector joining point A(9,12) and B(8,11)​

Step-by-step explanation:

x1=9  x2=8  y1=12  y2=11

=x2-x1

y2-y1

=8-91

1-12

=-1

-1

magintude =

=

=

=

direction=y component/x component

tan=-1/-1

tan=1

1=45

=45 degree

both x component and y component are negative so it lies on third quadrant.

the answer is 375 miles

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length