A lot is 60 m by 39 m. A house 28 m by 9 m is built on the lot. How much area is left over?
House
9 m
39 m
28 m
60 m
The area left over is ?

Area of lot = 60×39 = 2340 m²

Area of house = 28×9 = 252 m²

Area left over is = Area of lot - Area of house = 2340-252= 2088 m²

Step-by-step explanation:

area of the lot = length × breadth

= 60 × 39

= 2340 m²

area of the house = length × breadth

= 28 × 9

= 252 m²

area of the leftover portion = 2340 - 252

= 2088 m²

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3