What is the smallest of 3 consecutive odd numbers if the product of the smaller two integers is 3 less than 6 times the largest integer?

7,9,11

Step-by-step explanation:

Let first number is x, second number is (x+2) and third number is (x+4).

ATQ,

The product of the smaller two integers is 3 less than 6 times the largest integer.

x(x+2) = 6(x+4)-3

x² + 2x = 6x+24-3

x² + 2x = 6x+21

x² + 2x -6x -21=0

x²-4x -21=0

It is a quadratic equation whose solution is :

x = -3 and x = 7

First number = 7

Second number = 9

Third number = 11

Hence, this is the required ssolution.

you bought 31 v bucks

step-by-step explanation:

25+6=31