Find the area of the shape below

Q1) 104m²

Q2) 121 in.²

Step-by-step explanation:

Q1)

GIVEN :-

Figure given in the question comprises of a triangle & a rectangle.Length of the rectangle = 10 mWidth of the rectangle = 8 m Base of the triangle = 8 mHeight of the triangle = 6 m

TO FIND :-

Area of the figure

GENERAL FORMULAES TO BE USED IN THIS QUESTION :-

For a triangle with height 'h' & base 'b' , its area = .For a rectangle with length 'l' & width 'w' , its area =

SOLUTION :-

Area of the triangle =

Area of the rectangle =

Area of the figure = (Area of the triangle) + (Area of the rectangle)

                              = 24m²+ 80m²

                              = 104m²

Q2)

GIVEN :-

Figure given in the question comprises of a triangle & a trapezium.Lengths of parallel sides of trapezium are 6 in. & 7 in. Height of trapezium = 20 - 3 = 17 in.Base of the triangle = 3 in.Height of the triangle = 7 in.

TO FIND :-

Area of the figure

GENERAL FORMULAES TO BE USED IN THIS QUESTION :-

For a triangle with height 'h' & base 'b' , its area = .For a trapezium with parallel sides whose lengths are 'a' & 'b' and height 'h' , its area =

SOLUTION :-

Area of the triangle =

Area of the trapezium =

Area of the figure = (Area of the triangle) + (Area of the trapezium)

                              = 10.5 in.² + 110.5 in.²

                              = 121 in.²

Iwould say rat and vsu but i’m not 100% sure