A construction crew is using heavy equipment to dig a hole in which the foundation of a house will be built. The hole will be in the shape of a right rectangular prism with dimensions of 4 feet in depth, 100 feet long, and 50 feet wide.
The soil will be removed using a truck that can hold a maximum of 40,000 pounds. The soil weighs 90 pounds per
cubic foot. What is the least number of truckloads needed to remove all of the soil?

5

Step-by-step explanation: volume of hole = 100x50x4=20,000 ft

soil weighs : 20000x90=180,000 pounds

180,000 divided by 40,000 = 4.5 ≈ 5

So the least number of truckloads is 5

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.