Mathematics, 03.06.2021 07:30 blessed4628
An arrow is shot upward, with an initial velocity of 95 meters per second, at an angle of 48° with respect to the horizontal.
The arrow is shot from a helght of 5 meters above the ground.
The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after. It is shot
are given by the parametric equations below.
x=(vo cose)
y=-4.91? + (vo sin 6)e+h
Here vo is the initial velocity, 8 is the initial angle with respect to the horizontal, and h is the initial height.
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