The perimeter of the rectangle is 14 m and
the area is 12 m2.
Calculate the length
of the rectangle
diagonal​

5

Step-by-step explanation:

area of rectangle = l(ength)×w(idth)

perimeter = 2×l + 2×w

diagonal = sqrt(l² + w²) (Pythagoras)

l×w = 12. => l = 12/w

2×l + 2×w = 14

2×12/w + 2×w =14

12/w + w = 7

12 + w² = 7w

w² - 7w + 12 = 0

=> (after a little thinking and trying : what 2 numbers multiply to 12 and add to -7 ? -3 and -4

=> (w-3)×(w-4) = 0

so, we get 2 solutions for w : 3 and 4

that gives us 2 solutions for l : 4 and 3

so, one is 3 and the other 4. it does not matter which is which. length 4 and width 3 produce the same diagonal as length 3 and width 4.

diagonal = sqrt(l² + w²) = sqrt(16 +9) = sqrt(25) = 5

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: