A bag contains 5 yellow balls 3 red balls and 2 green balls. A ball is removed from the bag without looking, the colour recorded, and then returned the bag. A second ball is drawn and its colour is also recorded. c) What would be the outcome of the 2 balls if it has a probability of 1/10?

the two balls are yellow and green, in either order.

Step-by-step explanation:

P(Y) = 5/10 = 1/2

P(R) = 3/10

P(G) = 2/10

Since the only combination that makes a product of 1/10, so

P(Y)*P(G) = (5//10) * (2/10) = 10/100 = 1/10

So the two balls are yellow and green, in either order.

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400