the perimeter of a rectangle is 90m. The length is three less than five times the width. What is the length and the width of the rectangle?

length : 37 m

width : 8 m

Step-by-step explanation:

perimeter = 2×l(ength) + 2×w(idth) = 90

l = 5w - 3

=> 2×(5w-3) + 2w = 90

10w - 6 + 2w = 90

12w = 96

w = 8

=> l = 5w - 3 = 5×8 -3 = 40-3 = 37

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

24

step-by-step explanation: