In a group of 120 recruits at the police academy 80 are college graduates and 25 are army veterans. If 15 of the recruits are both college graduate and army veterans as shown above, how many are neither college graduate nor army veterans?

the number of recruits neither be college graduate and nor army veterans is 30

Step-by-step explanation:

The computation of the number of recruits neither be college graduate and nor army veterans is as follows;

= Total recruits - (college students + army veterans - both college graduates & army veterans)

= 120 recruits - (80 + 25 - 15)

= 120 recruits - 90  

= 30

hence, the number of recruits neither be college graduate and nor army veterans is 30

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;