A ladder leans against the wall at the point B (window end) from a ground level and makes an
angle horizontally at 52º. The height of ladder is 15
m. When the same ladder leans above the point B
at point A (window start) and makes an angle of 85°
horizontally. The distance between point A and
point B is

Step-by-step explanation:

Given:

The height of the ladder = 15 m

When the ladder leans at point B from the ground level, then it makes an angle  of 52° with the horizontal

When the ladder leans at point A from the ground level, then it makes an angle  of 85° with the horizontal

To find:

The distance between point A and point B is?

Solution:

To solve the above-given problem, we will use the following trigonometric ratio of a triangle:

Referring to the figure attached below, we will assume,

BD = AD = 15 m = height of the ladder

∠BDC = 52° = angle of elevation to the foot of the window

∠ADC = 85° = angle of elevation to the top of the window

Now,

In ΔBCD, we have

Opposite side = BC

Hypotenuse = BD = 15 m

θ = 52°

∴

and

In ΔACD, we have

Opposite side = AC

Hypotenuse = AD = 15 m

θ = 85°

∴

∴ The height of the window, AB = AC - BC = 14.94 m - 11.82 m = 3.12 m

Thus, the distance between point A and point B is 3.12 m.

Also View:

A ladder leaning against a wall makes an angle of 60 degree with the horizontal If the foot of the ladder is 2.5 m away from the wall , find the length of the ladder.

p> q if you calculate p is100 q is 79

a. -0.3 > -0.33