An amusement park has two featured rides that require an additional ticket, the Slingshot and the Scream Flyer. On a summer day, 1279 visitors entered the park. 280 visitors bought tickets for either the Slingshot or the Scream Flyer. 247 visitors bought a ticket for the Slingshot and 237 visitors bought a ticket for the Scream Flyer. What is the probability that a randomly selected visitor bought tickets for both the Slingshot and the Scream Flyer

Step-by-step explanation:

Formula for intersection:

n(A and B) = n(A)+n(B)-n(A or B)

Given: n(Slingshot) = 247

n(Scream Flyer)= 237

n(Slingshot or the Scream Flyer) = 280

n (Slingshot and Scream Flyer)= 247+237-280

=204

Probability of any event =

P(both the Slingshot and the Scream Flyer)=

Required probability =

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%