HELP ASAP Write an equation of a line that passes through the point (2,1) and is perpendicular to the line y=1/3x+2

y = -3x + 7

Step-by-step explanation:

a line perpendicular to y=1/3x + 2 must have a slope of -3 (the opposite reciprocal)

we can use slope (m) of -3 and the point (2,1) to write the equation:

y = mx + b

1 = (-3)(2) + b

1 = -6 + b

b = 7

Putting it all together you get:

y = -3x + 7

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step-by-step explanation: