Ricardo and John start swimming from the same location. Ricardo starts 15 seconds before John and swims at a rate of 3 feet per second. John swims at a rate of 4 feet per second in the same direction as
Ricardo. Which equation could you solve to find how long it will take John to catch up with Ricardo?
Does anyone know the answer?

t = (t₁ · vr)/ (vj - vr) = 45 seconds

Step-by-step explanation:

Given:

Initial time from Ricardo  t₁ = 15 seconds, Ricardo's velocity (speed) vr = 3 ft/s,

John's velocity (speed) vj = 4 ft/s

Requested time when John catch Ricardo t = ?

During 15 seconds, Ricardo moved away

S = vr · t₁ = 3 ft/s · 15 s = 45 feet.

From that moment, the same time runs for both of them

Ricardo's path is S₁ = vr · t  and John's path is S₂ = vj · t

S + S₁ = S₂ =>  S = S₂ - S₁  => 45 = vj · t - vr · t  

When we draw t we get:

t ( vj - vr) = 45   t = 45 / (vj - vr) = 45 / (4 - 3) = 45 / 1 = 45 seconds

t = 45 seconds

S₁ = vr · t = 3 · 45 = 135 ft

S₂ = vj · t = 4 · 45 = 180 ft

vwhat effect does the word head have on the meaning of this passage?

a. it demonstrates how intelligent he was.

b. it shows he was a favorite of the teachers.

c. it indicates he would be a good preacher.

d. it reveals how self-important he was.

how does the choice of the word head contribute to the passage’s tone?

a. it offers a sense of entitlement.

step-by-step explanation: