Josh graphed the function f(x) = -3(x-1)²+2. Then he graphed the function g(x) = -3(x-1)²-5 on the same coordinate plane. The vertex of g(x) is (1) 7 units below the vertex of f(x)
(2) 7 units above the vertex of f(x)
(3) 7 units to the right of the vertex of f(x)
(4) 7 units to the left of the vertex of f(x)