What is the magnetic field at the centre of a 10 loop-coil of wire of radius 10cm and carrying a current of 15A.​

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

8 2/3 is the answer

step-by-step explanation: just use a calculator

the answer is

d.

5.3066 m2

step-by-step explanation: