Given: sin (A) = 5/13, pi/2 < A < pi and tan (B) = - sqr root 13, pi/2 < B <. What is tan(A - B)? A. (5 + 12sqr root 13)/(12 - 5sqr root13) B. (12 - 5sqr root)/(5 + 12sqr root13) C. (12 + 5sqr root13)/(-5 + 12 sqr root13) D. (-5 + 12 sqr root13)/(12 + 5 sqr root13)

With these 5 geometry questions! pls 1.)quadrilateral abcd is inscribed in this circle.what is the measure of ∠a ? enter your answer in the box.°2.)quadrilateral abcd is inscribed in a circle.what is the measure of angle a? enter your answer in the box.m∠a= 3.)quadrilateral abcd is inscribed in this circle.what is the measure of angle b? enter your answer in the box.m∠b= °4.)quadrilateral abcd is inscribed in this circle.what is the measure of angle a? enter your answer in the box.°5.) quadrilateral abcd is inscribed in this circle.what is the measure of angle c? enter your answer in the box.°