There are 10 2/15 kg of watermelons and coconuts on a truck. The weight of the watermelons is 3 3/5 times that of the coconuts. How heavy are the coconuts on the truck, in kg?

2 7/76 kg

Step-by-step explanation:

Let the weight of

Watermelons = x

Coconut = y

There are 10 2/15 kg of watermelons and coconuts on a truck.

x + y = 10 2/15

x = 10 2/15 - y

x = 152/15 - y Equation 1

The weight of the watermelons is 3 3/5 times that of the coconuts.

x = 3 3/5 × y

x = 18/5 × y

x = 18y/5

How heavy are the coconuts on the truck, in kg?

Find y

We substitute 18y/5 for x in Equation 1

x = 152/15 - y

18y/5 = 152/15 - y

18y /5 + y = 152/15

Multiply through by 15

18y/5 × 15 + y × 15 = 152/15 × 15

3 × 18y + 15y = 152

54y + 15y = 152

69y = 152

y = 152/69

y = 2 14/152

y = 2 7/76 kg

Therefore, the weight of the coconuts are 2 7/76 kg

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

2 x 503

step-by-step explanation:

its 1006