if a box contains 7 red marbels, 6 white and 8 blue marbels and a marble is randomly selected from the box what is the probability that it is red expressed in fraction and in the simplest form​

1/3

Step-by-step explanation:

7 + 6 + 8 = 21 (There is a total of 21 marbles)

There are 7 red marbles, so the fraction should be 7/21 or 1/3

Have a great day :)

1/3

Step-by-step explanation:

How I got this answer is by adding 7+6+8 and I got 21. Then, I put the total of all of the marbles as the denominator which is 21. Next, I put 7 as the nominator so the fraction would be 7/21. Finally, I simplified 7/21 by 7 and I got 1/3.

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

answer: what are the answer choices?

step-by-step explanation: