Pascal wants to find the sum of the measures of the interior angles of a polygon that has n sides. How could he do this? Multiply 180 degrees by n. Multiply 180 degrees by (n + 2) Multiply 180 degrees by (n minus 2) Multiply 180 degrees by 2.

Multiply 180 degrees by (n minus 2)

Step-by-step explanation:

Number of sides in the polygon = n

Polygons have sides 3, 4, 5, 6

Polygon with 3 sides is a triangle

Polygon with 4 sides is a quadrilateral

Sum of it's Interior angles = (n-2) × 180°

For a 3 sided polygon

Sum of it's Interior angles = (n-2) × 180°

= (3 - 2) × 180°

= 1 × 180°

= 180°

For a 4 sided polygon

Sum of it's Interior angles = (n-2) × 180°

= (4 - 2) × 180°

= 2 × 180°

= 360°

Multiply 180 degrees by (n minus 2)

Step-by-step explanation:

x/3-10=8

x/3=18

x=48

answer: i guess 5 units?

step-by-step explanation: