Which equations have no real solution but have two complex solutions? A 3x>2-5=-8 b 2x>2=6x-5 c 12x=9x>2 +4 d -x>2 - 10x =34

Step-by-step explanation:

The equations are:

(a)

Add 8 to both sides

To do this, we simply calculate the discriminant (d) using:

If

Then it has complex roots

Where:

--- complex root

(b)

Equate to 0

--- complex root

(c)

Equate to 0

---- real roots

(d)

Equate to 0

---- complex root

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3