(x+3) (x+1) = x^2 +19

with steps

( x + 3 )( x + 1 ) = x^2 + 19

x^2 + ( 1 + 3 )x + ( 1 × 3 ) = x^2 + 19

x^2 + 4x + 3 = x^2 + 19

Subtract both sides x^2

x^2 - x^2 + 4x + 3 = x^2 - x^2 + 19

0 + 4x + 3 = 0 + 19

4x + 3 = 19

Subtract both sides 3

4x + 3 - 3 = 19 - 3

4x + 0 = 16

4x = 16

Divide both sides by 4

4x ÷ 4 = 16 ÷ 4

x = 4

( 4 + 3 )( 4 + 1 ) = 4^2 + 19

( 7 )( 5 ) = 16 + 19

35 = 35

Thus we found the correct value of x which is 4 .

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )