Write the equation of the quadratic whose Vertex is at ( −4,−5) and passes through the point (−3, −7)

To Find :

The equation of the quadratic whose Vertex is at ( −4,−5) and passes through the point (−3, −7).

Solution :

A quadratic equation in vertex form is given by :

( Here, h, k is the vertex )

y = a(x-(-4))² + (-5)

y = a(x+4)² - 5

Now, putting (-3,-7) in above equation:

-7 = a( -3 + 4 )² - 5

a(1)² = -2

a = -2

Therefore, the equation of the quadratic is y = -2(x+4)² - 5 .

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

c) yes, because of asa or aas