Given f’(x), where is f(x) increasing? Where is f(x) concave up?

See explanation below

Step-by-step explanation:

a. f(x) is increasing at (-∞, 1] and [7, ∞) because f'(x) is positive at those intervals.

b. f(x) is concave up at [4, ∞) because the slope of f'(x) or f''(x) is positive.

f(x) = y

f(-3) = -5

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)