A bag contains 9 marbles: 3 are green, 4 are red, and 2 are blue. Teresa chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that the first marble is blue and the second is green? Write
your answer as a fraction in simplest form.

Probability[First marble blue, second is green without replacement] = 1/12

Step-by-step explanation:

Given:

Number of green marble = 3

Number of red marble = 4

Number of blue marble = 2

Total marble = 9 marble

Find:

Probability[First marble blue, second is green without replacement]

Computation:

Probability of an event = Number of favorable outcome / Number of total outcome

Probability[First marble blue] = 2 / 9

Probability[second is green] = 3 / [9-1]

Probability[second is green] = 3 / 8

Probability[First marble blue, second is green without replacement] = Probability[First marble blue] x Probability[second is green]

Probability[First marble blue, second is green without replacement] = [2/9][3/8]

Probability[First marble blue, second is green without replacement] = 6 / 72

Probability[First marble blue, second is green without replacement] = 1/12

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.