Find the first three terms of the series represented by the formula 3(- 2)(n - 1).

0, - 6, - 12

Step-by-step explanation:

To find the first 3 terms, substitute n = 1, 2, 3 into the formula

a₁ = 3(- 2)(1 - 1) = 3 × - 2 × 0 = 0

a₂ = 3(- 2)(2 - 1) = 3 × - 2 × 1 = - 6

a₃ = 3(- 2)(3 - 1) = 3 × - 2 × 2 = - 12

First 3 terms are 0, - 6, - 12

no pictures of the graph

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3