Professor Rosencrantz flips a fair coin once. Professor Guildenstern flips a fair coin three times. What is the probability that Professor Rosencrantz obtains more heads than Professor Guildenstern

9/13 = 0.6923

Step-by-step explanation:

We start by defining

A as event that head was flipped

B1 = event that coin is biased

B2 = event that it is unbiased

P(B1) = 3/5

P(B2) = 2/5

P(A|B1) = 3/4

P(A|B2) = 2/4 = 1/2

When we solve this using bayes theorem we have to find

p(B1|A) = [P(B1) x P(A|B1)]/[P(B1) x P(A|B1) + P(B2) x P(A|B2)

= 0.6 x 0.75 / 0.6 x 0.75 + 0.4x0.5

= 0.45/0.45+0.2

= 0.45/0.65

= 0.6923

please brainliest

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

d no solution

step-by-step explanation: