An instructor has given a short quiz consisting of two parts. For a randomly selected student, let X be the number of points earned on the first part and Y be the number of points earned on the second part. Suppose that the joint probability mass function of X and Y is given in the accompanying table. Complete the following, writing only final numeric answers rounded to one decimal place. The expected value of X+Y = . Cov(X, Y) = .

x = -2

y = 848

step-by-step explanation:

plug in the numbers

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point