the mean of "n" numbers is "x" . if one more is added the mean is "y" . write an algebraic expression for the value of the number added?​

yn +y -xn

Step-by-step explanation:

Mean= sum of numbers ÷number of numbers

x= sum of n numbers ÷n

Multiply both sides by n:

xn= sum of n numbers

sum of n numbers= xn (1)

Let the number added be a.

After a has been added,

y= (sum of n numbers +a) ÷(n+1)

Multiply both sides by (n +1):

y(n +1)= sum of n numbers +a

sum of n numbers= y(n +1) -a (2)

Substitute (1) into (2):

xn= y(n +1) -a

Expand:

xn= yn +y -a

a= yn +y -xn

Let's check!

Let the numbers be 1, 2, 3 and 4.

mean, x= 10 ÷4= 2.5

n= 4

Let the new number added, a, be 7.

a= 7

mean, y= 17 ÷5= 3.4

a= yn +y -xn

a= 3.4(4) +3.4 -2.5(4)

a= 7

Thus, the expression is true.

y=mx+b is the final answer!   : )

c

step-by-step explanation: