Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 )

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

1) Determine the slope (m)

where two points that fall on the line are and

Plug in the given points (2,-5) and (8,-2)

Therefore, the slope of the line is . Plug this into :

2) Determine the y-intercept (b)

Plug in one of the given points and solve for b

Subtract 1 from both sides to isolate b

Therefore, the y-intercept of the line is -6. Plug this back into :

I hope this helps!

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752