Let 0 be an angle such that sec0= -13/12 and cot0<0. Find the exact values of tan0 and sin0.

Solution given;

Sec θ=-

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

cosθ=

=

b=12

h=13

By using Pythagoras law

p=

Now

exact values of tan θ==

since it lies in II quadrant

tan θ=-

and

sinθ==

since it lies in II quadrant

sin θ=

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e