No links please The length of a rectangle is 3x−2 and the width is x. x. If the area is 65ft^2, what is the width?
- my other one got deleted ;)

5 ft

Step-by-step explanation:

Area of a rectangle

length x width

(3x-2) * (x) = 65

3x^2 - 2x - 65 = 0

Δ/4 = 1 + 195 = 196

x1 = (1 + 14)/3 = 5

x2 (1-14)/3 = -13/3 (not acceptable because a length can’t be negative)

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752