Part A: Students from 4 towns attend a conference. Each town is assigned a number from 1 to 4. A number is drawn and replaced 6 times. Is this a fair way to pick 6 members to give each town representation?
YES or NO

Part B: What is the probability that Town 1 will have at least 1 representative after 6 number draws, to the nearest percent?
probability = %

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

the answer is c. 23/3

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it