A sketch of y = ax^2 + bx + c is shown. The minimum point is (1,-3) a) The value of a is
A: negative B: Zero C: positive

b) The value of c is
A: Negative B: zero c: positive

c) The solutions of ax^2 + bx + c = 0 are
A: both negative B: both positive C: one negative and one positive

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

idk

step-by-step explanation:

do a bckflip awfwgawgawggw